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($\frac{5}{6}$)x + 1 = ($\frac{216}{125}$)2x + 3
this is the same as
($\frac{5}{6}$)x + 1 = ($\frac{125}{216}$)-2x - 3; ($\frac{5}{6}$)x + 1 = ($\frac{5^3}{6^3}$)-2x - 3
($\frac{5}{6}$)x + 1 = ($\frac{5}{6}$)-3(2x + 3)
x + 1 = -6x - 9
7x = - 10; x = -$\frac{10}{7}$
johnmulu answered the question on March 6, 2017 at 07:12
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